Matematika
[tex]2 \sqrt{27} - 5 \sqrt{52} + 3 \sqrt{162} = [/tex]
[tex]2 \sqrt{ {3}^{3} } - 5 \sqrt{52} + 3 \sqrt{162} = [/tex]
[tex]2 \sqrt{ {3}^{2} } \sqrt{3} - 5 \sqrt{52} + 3 \sqrt{162} = [/tex]
[tex](2 \times 3 \sqrt{3} ) - 5 \sqrt{52} + 3 \sqrt{162} = [/tex]
[tex]6 \sqrt{3} - 5 \sqrt{52} + 3 \sqrt{162} = [/tex]
[tex]6 \sqrt{3} - 5 \sqrt{4 \times 13} + 3 \sqrt{162} = [/tex]
[tex]6 \sqrt{3} -( 5 \times 2 \sqrt{13} ) + 3 \sqrt{162} = [/tex]
[tex]6 \sqrt{3} - 10 \sqrt{13} + 3 \sqrt{162} = [/tex]
[tex]6 \sqrt{3} - 10 \sqrt{13} + (3 \sqrt{81 \times 2} ) = [/tex]
[tex]6 \sqrt{3} - 10 \sqrt{13} + (3 \sqrt{ {9}^{2} } \sqrt{2} ) = [/tex]
[tex]6 \sqrt{3} - 10 \sqrt{3} + (3 \times 9 \sqrt{2} ) = [/tex]
[tex]6 \sqrt{3} - 10 \sqrt{13} + 27 \sqrt{2} [/tex]
[answer.2.content]
